← Linear relations

Lines and regions

y = 2x + 1 is a line; y < 2x + 1 is every point below it. Draw the boundary (dashed if points on it are not included, solid if they are), then test a point to see which side to shade. Vertical lines are x = a; horizontal lines are y = a.

A delivery zone, a speed limit, a budget: often the answer is not one point but a whole region of points that work.

You can graph a line from its rule, such as y=2x+1y = 2x + 1. Now: what about y<2x+1y < 2x + 1? Every point whose yy is less than 2x+12x + 1 makes it true, and those points fill a whole region of the graph.

You also meet lines with only one letter: x=3x = 3 (vertical) and y=−2y = -2 (horizontal).

PredictRead the problem and decide what you think before you try anything. A wrong guess is fine: it shows you what to look for.

In or out?

Put x=1x = 1 and y=4y = 4 into y<2x+1y < 2x + 1. Is it true?

Is the point (1,4)(1, 4) in the region y<2x+1y < 2x + 1?

TryTry it on the board and compare the result with your prediction.

Into the region

Try a point on the dashed line too. Does it make y<2x+1y < 2x + 1 true?

Try it yourselfYour edits are saved in this browser.

Drag PP into the shaded region y<2x+1y < 2x + 1. Check its coordinates in the inequality. Was your prediction right about (1,4)(1, 4)?

Use the board. This ticks when you get there.

InvestigateWork out why it happens, one step at a time.

Boundary, then test

Here is how to graph an inequality.

Worked exampleBefore each step, say what you think comes next.
  1. y<2x+1y < 2x + 1The boundary is the line y=2x+1y = 2x + 1.

Solid or dashed for y≥x−2y \ge x - 2?

Read Ana's working. Which line does not match the sign?

Need a hint?

The orange region is x ≥ 3: on or right of x = 3.

Another hint

The other is y < 2: below the dashed line y = 2.

Try it yourselfYour edits are saved in this browser.
For y≥x−2y \ge x - 2, is the boundary line solid or dashed?

Ana graphs y>x+1y > x + 1. Click the line where her working goes wrong.

Two regions: x≥3x \ge 3 and y<2y < 2. Drag PP to a point that is in both.

Use the board. This ticks when you get there.

ModifyChange the problem on purpose and see what happens.

One change at a time

Each task changes one thing.

Need a hint?

x = −2 is the vertical line; y = 3 the horizontal one.

A shaded region with a solid boundary.
A shaded region with a solid boundary.
Need a hint?

On the line: y = 4 − x. The boundary is solid, so those points count.

The region y < 3.
The region y<3y < 3.
Try it yourselfYour edits are saved in this browser.

Drag PP to where x=−2x = -2 meets y=3y = 3.

Use the board. This ticks when you get there.

Which inequality is shaded?

The region is y≤−x+4y \le -x + 4. Drag PP to a point on its boundary line.

Use the board. This ticks when you get there.

Is (2,5)(2, 5) in the region y>2x+1y > 2x + 1?

Edge case: which points are in y<3y < 3?

PractiseA few on your own, to check you have it.

Regions

Which point is in y≤3x−2y \le 3x - 2?

Which has a dashed boundary?

Which line is vertical?

Review: what are the gradient and y-intercept of y=3x−2y = 3x - 2?

MakeMake your own problem using what you have learned. Expect a few tries; that is normal.

Fit the region

Find two different answers. What do they have in common?

Try it yourselfYour edits are saved in this browser.
Need a hint?

(0, 0) in y ≤ mx + c means 0 ≤ c.

Another hint

(0, 3) outside means c is less than 3. Then check B (2, 1): 1 ≤ 2m + c.

Set mm and cc so the region y≤mx+cy \le mx + c contains A(0,0)A(0, 0) and B(2,1)B(2, 1) but not C(0,3)C(0, 3).

Use the board. This ticks when you get there.

For teachers

Students graph vertical and horizontal lines and linear inequalities as regions, choosing a dashed or solid boundary and testing a point to decide which side to shade (AC9M8A02, node 1). About 45 minutes.

Open the teacher guide: answers, solutions, slides and a worksheet.

Students will be able to

Before class

Do the Run board and the Make task yourself first. Students need Lines and their rules (gradient and intercept).

The one idea: an inequality is every point that makes it true; the line is its boundary, dashed when the line's points are left out (< and >) and solid when they are in (≤ and ≥). The common mistake is the wrong boundary style; it is planted in Ana's working.

Running the lesson

  1. Predict: take a show of hands. Students who chose yes compared 4 with 1, not with 2 × 1 + 1.
  2. Run: ask students to read out a point in the region and check it aloud.
  3. Investigate: model the boundary-then-test routine with (0, 0); ask when (0, 0) would be a bad test point (when it is on the line).
  4. Modify: before the vertical line task, ask what every point on x = −2 has in common.
  5. Make: collect students' m and c and test C in each.

When students get stuck

Stretch and support

Stretch: Shade the region where y ≥ x and y < 4 and x > 0 (a triangle). What are its corners?

Support: Use the Run board: drag P and read whether the coordinates make the inequality true.

Where it leads

Next: Solving with graphs, then (in Algebra) Inequalities, which solves one-variable inequalities and checks them graphically.

Where it leads: linear programming and simultaneous inequalities (Years 10 and up).

What each step is for

Now you can
Practise this skillNew questions, new numbers each timeGet 3 right in a row to mark it practised.Next lesson9. Solving equations with graphsDraw each side of an equation as a line. Where the lines meet, both sides are equal, so the x there is the solution.