← Teacher guide

Unknown angles in shapes

Students find unknown angles in triangles, quadrilaterals and pentagons in steps, with a reason for each (angle sum, straight line, isosceles), and explain why an exterior angle equals the sum of the two interior opposite angles; working is their own, the answer and a key reason are marked (AC9M7M05, node 3).

Angles and shapes · Angle sums · about 45 minutes · Open the student lesson

Classroom resources

Load these into Waypoints Prepare: choose Load URL and paste the copied address, or download the file and import it. In Prepare, the worksheet's Teacher edition shows the answers; the student copy hides them.

Students will be able to

Timing

Predict and Run 8 min · Investigate 15 min · Modify 12 min · Practise and Make 10 min

Before class

Do the first reasoning task yourself, then compare with its model. Students need Angles in a triangle, Angles in a polygon and Reasoning with angles.

The one idea: choose the right angle sum for the shape, then chain steps with reasons. The common mistake is using 180° for every shape; it is planted in Zoe's working, where a negative angle is the clue.

As in Reasoning with angles, the free working is not marked: students write it their way. The answer is marked, and at the key step they choose the reason from a list. Then they compare with a model and tick a self-check. The isosceles task is wider than the minimum: the equal angles are stated in the question.

Running the lesson

  1. Predict: take a show of hands, then ask students who chose 110° how they got it. Collect both routes (two steps, or a + b).
  2. Run: ask why x = a + b must be true (a + b + c = 180° and x + c = 180°).
  3. Investigate: model know, choose, say why for the triangle. Ask: what does a negative answer tell you (Zoe)?
  4. Modify: before the pentagon, ask students for its angle sum and how they know.
  5. Make: ask students what c must be before they move anything.

When students get stuck

What you will seeA question to askThe fix
A student uses 180° for a quadrilateral (Zoe's mistake).How many triangles does a quadrilateral split into?(n − 2) × 180°: two triangles, 360°.
A student stops at the interior angle when asked for the exterior one.Which angle is x? Is it inside the triangle?Mark x on the diagram, then find what links it to an angle you have (a straight line).
A student writes numbers with no reasons.Which fact did you use for that line?One reason per line, in short words: 'angle sum of triangle', 'straight line'.

Answers to the checks

  1. the outside angle: A triangle has a=50∘a = 50^\circ and b=60∘b = 60^\circ. The side through CC is extended past CC, making an outside angle xx with the third side. What is xx?
    110°. c = 180° − 50° − 60° = 70° (angles in a triangle), then x = 180° − 70° = 110° (a straight line). Notice: 110° = 50° + 60°.
  2. drag the triangle: Drag the corners (or use Move) until xx is more than 120∘120^\circ. Each time, compare xx with a+ba + b.
  3. Triangle, then a straight line: Find xx. Write each step with its reason.
    c=180∘−59∘−45∘=76∘c = 180^\circ - 59^\circ - 45^\circ = 76^\circ (angles in a triangle add to 180∘180^\circ); x=180∘−76∘=104∘x = 180^\circ - 76^\circ = 104^\circ (cc and xx are on a straight line)
    c = 76° (angles in a triangle), x = 104° (a straight line with c). Check: 59° + 45° = 104°.
  4. Find the mistake: Zoe finds the fourth angle of a quadrilateral. Click the line where her working goes wrong.
    line 2
    Line 2: a quadrilateral's angles add to (4 − 2) × 180° = 360°, not 180°. d = 360° − 76° − 68° − 102° = 114°. A negative angle on line 4 is the clue that something earlier went wrong.
  5. A quadrilateral: Find dd, with your reason.
    a+b+c+d=360∘a + b + c + d = 360^\circ (angles in a quadrilateral: (4−2)×180∘(4 - 2) \times 180^\circ); d=360∘−76∘−68∘−102∘=114∘d = 360^\circ - 76^\circ - 68^\circ - 102^\circ = 114^\circ (subtract the angles you know)
    (4 − 2) × 180° = 360°, so d = 360° − 246° = 114°.
  6. Isosceles: CA=CBCA = CB, so the angles at AA and BB are equal. Find cc, with a reason for each step.
    b=56∘b = 56^\circ (isosceles triangle: the angles opposite the equal sides are equal); c=180∘−56∘−56∘=68∘c = 180^\circ - 56^\circ - 56^\circ = 68^\circ (angles in a triangle add to 180∘180^\circ)
    b = 56° (isosceles), c = 68° (angles in a triangle).
  7. A pentagon: Find ee.
    98
    (5 − 2) × 180° = 540°, so e = 540° − 442° = 98°.
  8. Exterior at another corner: Find the exterior angle xx at BB.
    b=180∘−63∘−87∘=30∘b = 180^\circ - 63^\circ - 87^\circ = 30^\circ (angles in a triangle add to 180∘180^\circ); x=180∘−30∘=150∘x = 180^\circ - 30^\circ = 150^\circ (bb and xx are on a straight line)
    b = 30°, x = 150°. Or straight away: x = a + c = 63° + 87° = 150° (the exterior angle equals the sum of the two interior opposite angles).
  9. A right angle: Find cc.
    100
    360° − 68° − 90° − 102° = 100°.
  10. Impossible triangles: Edge case: can a triangle have two angles of 100∘100^\circ?
    No: they already add to more than 180°
    100° + 100° = 200° > 180°, so no. A triangle has at most one obtuse angle.
  11. Triangle: A triangle has angles of 35∘35^\circ and 85∘85^\circ. Find the third angle.
    60
    180° − 35° − 85° = 60°.
  12. Quadrilateral: Three angles of a quadrilateral are 90∘90^\circ, 85∘85^\circ and 120∘120^\circ. Find the fourth.
    65
    360° − 295° = 65°.
  13. Exterior angle backwards: A triangle has an exterior angle of 130∘130^\circ at CC, and a=70∘a = 70^\circ. Find bb, with your reasons.
    c=180∘−130∘=50∘c = 180^\circ - 130^\circ = 50^\circ (cc and the exterior angle are on a straight line); b=180∘−70∘−50∘=60∘b = 180^\circ - 70^\circ - 50^\circ = 60^\circ (angles in a triangle add to 180∘180^\circ)
    c = 50°, b = 60°. Or: 130° = a + b, so b = 60°.
  14. Review: parallel lines: Review: parallel lines, c=70∘c = 70^\circ. Which is a correct first step to find ee?
    e=110∘e = 110^\circ: co-interior with cc
    Co-interior angles add to 180°: e = 110°.
  15. a given exterior angle: Move the corners so that the exterior angle xx is 135∘135^\circ.

    c = 45°, so a + b = 135°: for example a = 90° and b = 45°.

Solutions

One possible solution for each task. Other correct programs are fine.

one change at a time › Isosceles

Open task: any program that does what the step asks.

one change at a time › A pentagon

Open task: any program that does what the step asks.

one change at a time › Exterior at another corner

Open task: any program that does what the step asks.

one change at a time › A right angle

Open task: any program that does what the step asks.

one change at a time › Impossible triangles

Open task: any program that does what the step asks.

a given exterior angle

Open task: any program that does what the step asks.

Stretch and support

Stretch: Prove that the exterior angles of any convex polygon add to 360°, starting from a triangle (each exterior + interior = 180°).

Support: Use the Run board to check: set a triangle, read its angles, and compare with your working.

Coach prompt (optional)

For a student who has done the lesson and is still stuck. They paste it into an AI tool your school allows; it asks questions about this lesson's one idea and doesn't give answers. Students see it on the course recap page only through a link ending in ?coach=1: recap with coach prompts.

You are a patient maths coach for a Year 7 student in Australia. Help me understand ONE idea only, from the lesson "Unknown angles in shapes".

The idea: Finding unknown angles using angle sums: I can Students use triangle and polygon angle sum properties to find unknown angles, giving reasons.

What understanding looks like:
- Correctly finds unknown angles using angle sum properties.
- States the property used as the reason for each step.
- Applies the correct angle sum for the polygon type.

Mistakes students often make here:
- A student uses 180° for a quadrilateral (Zoe's mistake).
- A student stops at the interior angle when asked for the exterior one.
- A student writes numbers with no reasons.

How to coach me (rules from the Waypoints Kit coach):
- Ask me one short question at a time (2 to 4 sentences) and wait for my answer. Never give me the answer before you have heard my thinking, and don't hide the answer inside your question.
- Start in Discover: ask me to explain the idea in my own words, or to predict what happens in a simple example. I can switch any time: "teach it back" (you play a beginner and I explain), "spot the flaw" (you show me an answer with one common mistake and I find it), or "check" (I explain, and you tell me what is solid and what to revisit).
- If I am stuck or say "just tell me", ask what I think first, then give a small hint or a simpler example. Explain only after I have had a real go.
- If I seem to be missing the idea that comes before this one (Interior angle sum of polygons by decomposition), check it quickly, then come back.
- Stay in this idea: don't teach later ideas or add extra content. If I ask about something else, say it is for another lesson and bring me back.
- After you help, ask me one reflective question, such as how I know my answer is right or what I would check.
- Praise my effort and method, not my ability.
- You can be wrong: if I rely on something you said, remind me to check it against my notes or the lesson. If you don't know, say so.
- Use simple words.
- Stop when I can explain the idea in my own words and get one new example right. Then tell me to go back to the lesson "Unknown angles in shapes".

Exit ticket

A triangle has angles of 48° and 67°. Find the third angle, and the exterior angle next to it, with reasons.

180° − 48° − 67° = 65° (angles in a triangle). Exterior angle 180° − 65° = 115° (a straight line). Check: 48° + 67° = 115°.

What each step is for

Where it leads

This completes the Year 7 angle work: parallel lines (AC9M7M04) and angle sums (AC9M7M05).

Where it leads: congruence and similarity (Years 8 and 9) and geometric proof, where chains of reasons are the whole point.