← Teacher guide

Reasoning with angles

Students find unknown angles at parallel lines in two-step chains, with a reason for each step, writing their working their own way; the platform marks the answer and the reason at the key step, then shows a model to compare with (AC9M7M04, node 3).

Angles and shapes · Parallel lines · about 45 minutes · Open the student lesson

Classroom resources

Load these into Waypoints Prepare: choose Load URL and paste the copied address, or download the file and import it. In Prepare, the worksheet's Teacher edition shows the answers; the student copy hides them.

Students will be able to

Timing

Predict and Run 8 min · Investigate 15 min · Modify 12 min · Practise and Make 10 min

Before class

Do the first reasoning task yourself first, then compare with its model. Students need both parallel-lines lessons and Year 6 angle facts (straight line, vertically opposite, at a point).

The one idea: know, choose the rule, say why. Every angle found needs a named reason. The common mistake is linking two angles that only look related (Kai's b and e); it is planted after the routine.

The reasoning tasks do not mark the free working: students write it their own way (notes, abbreviations such as "vert. opp." and "co-int." are fine). The answer is marked, and at one key step students choose the reason from a list, so the misconception gets feedback. Then they compare their working with a model and tick a short self-check. Look at the working in class: it is where reasoning shows.

Running the lesson

  1. Predict: take a show of hands. Students who chose 70° are assuming b and h are linked directly.
  2. Run: ask students to say the two rules that make h = 180° − b true for every crossing angle.
  3. Investigate: model know, choose, say why on the board, writing the reason in short form. Accept any correct route.
  4. Modify: collect two different routes to f and ask which is shorter.
  5. Make: ask students to say their two steps before they turn the line.

When students get stuck

What you will seeA question to askThe fix
A student links two angles that only look related (Kai's mistake).Which rule links them? Name it.If no rule links them directly, find an angle in between that does.
A student gets the right angle with no reasons.How would you convince someone who did not see the diagram?Write one reason per line: the angle, then why.
A student cannot find a first step.Which angles can you find straight from the given one?List every angle one rule away from the given one; the target is usually among those, or one more step on.

Answers to the checks

  1. two steps: Two parallel lines are crossed by a transversal. b=70∘b = 70^\circ. What is hh?
    110°. b and h are not a named pair, so it takes two steps: f = 70° (corresponding to b), then h = 180° − 70° = 110° (f and h are on a straight line).
  2. check the chain: Turn the crossing line until b=70∘b = 70^\circ, then pick bb and hh. Was your prediction right?
  3. Know, choose, say why: Find hh. Write each step with its reason.
    f=70∘f = 70^\circ (corresponding to bb: corresponding angles are equal); h=180∘−70∘=110∘h = 180^\circ - 70^\circ = 110^\circ (ff and hh are on a straight line)
    f = 70° (corresponding to b), h = 110° (a straight line with f). Another route: d = 110° (a straight line with b), h = 110° (corresponding to d).
  4. Find the mistake: Kai finds ee when b=70∘b = 70^\circ. Click the line where his reasoning goes wrong.
    line 2
    Line 2: b and e are not a named pair (b is above the top line, e above the bottom line, on different sides). Looking related is not a reason. e = 110°: f = 70° (corresponding to b), then e = 180° − 70° (a straight line).
  5. Another chain: Find gg. Write each step with its reason.
    e=115∘e = 115^\circ (alternate to dd: alternate angles are equal); g=180∘−115∘=65∘g = 180^\circ - 115^\circ = 65^\circ (ee and gg are on a straight line)
    e = 115° (alternate to d), g = 65° (a straight line with e). Or: f = 65° (co-interior with d), g = 65° (vertically opposite f).
  6. A different start: Find ff, with a reason for each step.
    e=130∘e = 130^\circ (corresponding to aa); f=180∘−130∘=50∘f = 180^\circ - 130^\circ = 50^\circ (ee and ff are on a straight line)
    e = 130° (corresponding to a), f = 50° (a straight line with e). Or b = 50° (a straight line with a), f = 50° (corresponding to b).
  7. Up from the bottom: Find bb, going up from the bottom line.
    c=180∘−140∘=40∘c = 180^\circ - 140^\circ = 40^\circ (co-interior with ee: co-interior angles add to 180∘180^\circ); b=40∘b = 40^\circ (vertically opposite cc)
    c = 40° (co-interior with e), b = 40° (vertically opposite c).
  8. Your own route: Find cc. (Use your own steps; two are enough.)
    55
    d = 125° (corresponding to h), then c = 55° (a straight line with d).
  9. Not parallel: Are these two lines parallel?
    No: c and f are alternate angles, but they are not equal
    If the lines were parallel, the alternate angles c and f would be equal. They are not, so the lines are not parallel.
  10. Showing lines are parallel: Backwards: tilt the lower line until the alternate angles cc and ff are equal. What does that tell you about the lines?

    When alternate angles are equal, the lines are parallel (w = 0). Equal corresponding or alternate angles, or co-interior angles adding to 180°, show that lines are parallel.
  11. Down the page: Find aa, with a reason for each step.
    c=75∘c = 75^\circ (corresponding to gg); a=180∘−75∘=105∘a = 180^\circ - 75^\circ = 105^\circ (aa and cc are on a straight line)
    c = 75° (corresponding to g), a = 105° (a straight line with c).
  12. Through the middle: Find hh, with a reason for each step.
    e=180∘−80∘=100∘e = 180^\circ - 80^\circ = 100^\circ (co-interior with cc); h=100∘h = 100^\circ (vertically opposite ee)
    e = 100° (co-interior with c), h = 100° (vertically opposite e). Or g = 80° (corresponding to c), h = 100° (a straight line with g).
  13. Review: one crossing: Review: Tom says "bb and cc are alternate angles". Which is right?
    They are vertically opposite: both at the top crossing
    b and c are at the same crossing, opposite each other: vertically opposite (and equal for that reason).
  14. set it up: Work out what bb must be for h=125∘h = 125^\circ. Then turn the crossing line until bb is that size: only bb is shown, and this ticks when h=125∘h = 125^\circ.

    f = 55° (a straight line with h), so b = 55° (corresponding to f).

Solutions

One possible solution for each task. Other correct programs are fine.

one change at a time › A different start

Open task: any program that does what the step asks.

one change at a time › Up from the bottom

Open task: any program that does what the step asks.

one change at a time › Your own route

Open task: any program that does what the step asks.

one change at a time › Not parallel

Open task: any program that does what the step asks.

one change at a time › Showing lines are parallel

Open task: any program that does what the step asks.

set it up

Open task: any program that does what the step asks.

Stretch and support

Stretch: Write a three-step puzzle for a partner: give one angle, ask for an angle three rules away, and write the model reasons.

Support: Allow the Run board for checking each step: set the given angle, pick pairs and read the names.

Coach prompt (optional)

For a student who has done the lesson and is still stuck. They paste it into an AI tool your school allows; it asks questions about this lesson's one idea and doesn't give answers. Students see it on the course recap page only through a link ending in ?coach=1: recap with coach prompts.

You are a patient maths coach for a Year 7 student in Australia. Help me understand ONE idea only, from the lesson "Reasoning with angles".

The idea: Using angle reasoning to solve problems: I can Students solve multi-step angle problems involving parallel lines, giving geometric reasons for each step.

What understanding looks like:
- Solves a multi-step angle problem correctly.
- States a geometric reason for each step.
- Does not assume angle values without justification.

Mistakes students often make here:
- A student links two angles that only look related (Kai's mistake).
- A student gets the right angle with no reasons.
- A student cannot find a first step.

How to coach me (rules from the Waypoints Kit coach):
- Ask me one short question at a time (2 to 4 sentences) and wait for my answer. Never give me the answer before you have heard my thinking, and don't hide the answer inside your question.
- Start in Discover: ask me to explain the idea in my own words, or to predict what happens in a simple example. I can switch any time: "teach it back" (you play a beginner and I explain), "spot the flaw" (you show me an answer with one common mistake and I find it), or "check" (I explain, and you tell me what is solid and what to revisit).
- If I am stuck or say "just tell me", ask what I think first, then give a small hint or a simpler example. Explain only after I have had a real go.
- If I seem to be missing the idea that comes before this one (Properties of corresponding, alternate and co-interior angles), check it quickly, then come back.
- Stay in this idea: don't teach later ideas or add extra content. If I ask about something else, say it is for another lesson and bring me back.
- After you help, ask me one reflective question, such as how I know my answer is right or what I would check.
- Praise my effort and method, not my ability.
- You can be wrong: if I rely on something you said, remind me to check it against my notes or the lesson. If you don't know, say so.
- Use simple words.
- Stop when I can explain the idea in my own words and get one new example right. Then tell me to go back to the lesson "Reasoning with angles".

Exit ticket

A transversal crosses two parallel lines, making a 120° angle. Find the angle alternate to it and the angle co-interior to it, with reasons.

120° (alternate angles are equal) and 180° − 120° = 60° (co-interior angles add to 180°).

What each step is for

Where it leads

Next: angle sums of triangles and polygons, then Unknown angles in shapes, which combines them with these rules.

Where it leads: geometric proof (Years 8 to 10), where a chain of reasons is the proof.