---
title: "Area of triangles"
subtitle: "Area, volume, circles and Pythagoras · Area · Lesson 2"
---

# Area of triangles

**Name:** {{field-24}} **Date:** {{field-15}} **Class:** {{field-15}}

> **Key question:** Sails, roof gables and the slices of a pizza cut into wedges are triangles. How much fabric does a triangular sail need?


:::teacher-note

**In one sentence:** Students double a triangle with a turned copy to make a parallelogram, see why A = ½bh, find heights that fall outside obtuse triangles, and work backwards from an area (AC9M7M01, node 1).

**Students should be able to say:** I can explain why a triangle's area is half of base × height. I can find the area of any triangle, including one whose height falls outside it. I can find a missing base or height from an area.

**Width:** the unmarked parts are the floor every student does (predict, run, investigate and make). Typical adds the modify practice; wider adds the real-world contexts. They add contexts, not difficulty. Students work in the online tutorial alongside this sheet.

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## Predict

How would two copies of the triangle fit together?

:::keep-together

**A triangle has base 6 cm and perpendicular height 4 cm. What is its area?**

☐ 20 cm²

☐ 24 cm²

☐ 10 cm²

☐ 12 cm²

My prediction, and why:

{{lines-3}}

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:::teacher-note

**What happens:** 12 cm². Two copies make a 6 by 4 parallelogram, 24 cm², so one triangle is half: 12 cm². 24 is the parallelogram.

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## Run

Try it on the board in the tutorial. Was your prediction right? What was different?

{{lines-2}}

## Half of base times height


:::keep-together

### Halve it

Here is the reason, then the routine.

1. $6 \times 4 = 24$ — Two copies of the triangle make a parallelogram with the same base and height.
2. $A = \tfrac{1}{2} \times 6 \times 4 = 12 \text{ cm}^2$ — One triangle is half of it.
3. $A = \tfrac{1}{2} \times 10 \times 7 = 35 \text{ cm}^2$ — Multiply the base by the height, then halve (or halve first: 5 × 7).

Now try one: base 10 cm, height 7 cm.

**A triangle has base 10 cm and perpendicular height 7 cm. What is its area, in cm²?**

Answer: {{field-15}}

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:::teacher-note

**Answer:** 35

½ × 10 × 7 = 35 cm².

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:::keep-together

### Find the mistake

**Omar finds the area of a triangle. Click the line where his working goes wrong.**

```
 1  A triangle has base 8 cm and perpendicular height 5 cm.
 2  Area = base × height
 3  = 8 × 5
 4  = 40 cm²
```

Line: {{field-15}}

Why is it wrong?

{{lines-2}}

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:::teacher-note

**Answer:** line 2

Line 2: a triangle is half of base × height. ½ × 8 × 5 = 20 cm².

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:::keep-together

### A height outside

**Where is this triangle's perpendicular height?**

☐ It has no height, because the top is not above the base

☐ Along the longest side

☐ Outside the triangle: straight down from the top to the base, extended

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:::teacher-note

**Answer:** Outside the triangle: straight down from the top to the base, extended

Extend the base (dashed) and drop the height from the top at a right angle. The area is still ½ × 4 × 4 = 8 cm².

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:::typical

## One change at a time


**A height outside.** Each task changes one thing.

**Area 12.** 

**Another triangle.** 

**Backwards: the height.** 

**A right angle.** 

Work in the tutorial. Plan first: what will you change, and how will you test it?

{{box-4}}

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## Triangles


:::keep-together

### Halve it

**Base 12 m, perpendicular height 5 m. Area, in m²?**

Answer: {{field-15}}

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:::teacher-note

**Answer:** 30

½ × 12 × 5 = 30 m².

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:::keep-together

### A decimal answer

**Base 7 cm, perpendicular height 3 cm. Area, in cm²?**

Answer: {{field-15}}

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:::teacher-note

**Answer:** 10.5

½ × 7 × 3 = 10.5 cm².

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:::keep-together

### Half a rectangle

**A 10 cm by 6 cm rectangle is cut along a diagonal. What is the area of one triangle, in cm²?**

Answer: {{field-15}}

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:::teacher-note

**Answer:** 30

Half of 10 × 6 = 60: 30 cm².

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:::keep-together

### Review: parallelograms

**Review: a parallelogram has base 7 cm and perpendicular height 6 cm. Area, in cm²?**

Answer: {{field-15}}

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:::teacher-note

**Answer:** 42

7 × 6 = 42 cm².

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## Make: area 15

Then find a second triangle with the same area and a different base.

Work in the tutorial. Plan first: what will you change, and how will you test it?

{{box-4}}

## Exit ticket

:::keep-together

**A triangle has base 9 cm and height 6 cm. Find its area. A triangle with area 24 cm² has base 8 cm: find its height.**

{{lines-3}}

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:::teacher-note

**Answer:** ½ × 9 × 6 = 27 cm². ½ × 8 × h = 24, so h = 6 cm.

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