---
title: "Right, acute or obtuse?"
subtitle: "Area, volume, circles and Pythagoras · Pythagoras · Lesson 11"
---

# Right, acute or obtuse?

**Name:** {{field-24}} **Date:** {{field-15}} **Class:** {{field-15}}

> **Key question:** Given only three lengths, can you tell whether a triangle has a right angle, without drawing it? Builders do exactly this when they mark out a square corner with a tape measure.


:::teacher-note

**In one sentence:** Students open and close the angle between two sides to see that c² = a² + b² only at 90°, then use the comparison to classify triangles from their side lengths as right-angled, acute or obtuse, and hunt for Pythagorean triples (AC9M8M06, node 3).

**Students should be able to say:** I can tell from three side lengths whether a triangle is right-angled, acute or obtuse. I can explain why the longest side must be c in the test. I can find and check Pythagorean triples.

**Width:** the unmarked parts are the floor every student does (predict, run, investigate and make). Typical adds the modify practice; wider adds the real-world contexts. They add contexts, not difficulty. Students work in the online tutorial alongside this sheet.

:::


## Predict

Compare $4^2 + 5^2$ with $6^2$.

:::keep-together

**A triangle has sides 4 cm, 5 cm and 6 cm. Is it right-angled, acute or obtuse?**

☐ Acute

☐ Obtuse

☐ Right-angled

My prediction, and why:

{{lines-3}}

:::


:::teacher-note

**What happens:** Acute. 4² + 5² = 16 + 25 = 41, and 6² = 36. The two squares are more than the longest one, so the biggest angle is less than 90°.

:::


## Run

Try it on the board in the tutorial. Was your prediction right? What was different?

{{lines-2}}

## Compare the squares


:::keep-together

### The test

Here is the test, step by step.

1. $c = 13 \text{ (the longest)}$ — Choose the longest side as c.
2. $5^2 + 12^2 = 25 + 144 = 169$ — Square the other two and add.
3. $13^2 = 169$ — Square the longest.
4. $169 = 169 \Rightarrow \text{right-angled}$ — Equal: right-angled. Less: obtuse. More: acute.

Now try one: sides 6, 8 and 11.

**A triangle has sides 6 cm, 8 cm and 11 cm. Is it right-angled, acute or obtuse?**

☐ Right-angled

☐ Acute

☐ Obtuse

:::


:::teacher-note

**Answer:** Obtuse

6² + 8² = 100 is less than 11² = 121: the angle opposite 11 is more than 90°, obtuse.

:::


:::keep-together

### Find the mistake

**Ava tests whether a triangle is right-angled. Click the line where her method goes wrong.**

```
 1  Is a triangle with sides 5, 13 and 12 right-angled?
 2  5² + 13² = 25 + 169 = 194
 3  12² = 144
 4  194 is not 144, so it is not right-angled.
```

Line: {{field-15}}

Why is it wrong?

{{lines-2}}

:::


:::teacher-note

**Answer:** line 2

Line 2: c must be the longest side, 13. Test 5² + 12² = 25 + 144 = 169 = 13²: it is right-angled.

:::


:::keep-together

### Triples

**3, 4, 5 is a Pythagorean triple. Which of these is also one?**

☐ 3, 4, 6

☐ 6, 8, 10

☐ 4, 5, 6

☐ 5, 6, 7

:::


:::teacher-note

**Answer:** 6, 8, 10

6, 8, 10 is 3, 4, 5 doubled: 36 + 64 = 100 = 10².

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:::typical

## One change at a time


**Acute on the board.** Each task changes one thing.

**A triple?.** 

**Just obtuse.** 

**Not a triangle.** 

Work in the tutorial. Plan first: what will you change, and how will you test it?

{{box-4}}

:::


## Right, acute or obtuse


:::keep-together

### Right

**Sides 9, 12 and 15?**

☐ Obtuse

☐ Right-angled

☐ Acute

:::


:::teacher-note

**Answer:** Right-angled

81 + 144 = 225 = 15²: right-angled (3, 4, 5 times 3).

:::


:::keep-together

### Acute

**Sides 5, 6 and 7?**

☐ Obtuse

☐ Right-angled

☐ Acute

:::


:::teacher-note

**Answer:** Acute

25 + 36 = 61 is more than 7² = 49: acute.

:::


:::keep-together

### Obtuse

**Sides 3, 5 and 7?**

☐ Right-angled

☐ Obtuse

☐ Acute

:::


:::teacher-note

**Answer:** Obtuse

9 + 25 = 34 is less than 7² = 49: obtuse.

:::


:::keep-together

### Review: a side

**Review: hypotenuse 10 cm, one side 6 cm. The other side, in cm?**

Answer: {{field-15}}

:::


:::teacher-note

**Answer:** 8

100 − 36 = 64, √64 = 8 cm.

:::


## Make: a new triple

Then: is the triple you found a multiple of another one?

Work in the tutorial. Plan first: what will you change, and how will you test it?

{{box-4}}

## Exit ticket

:::keep-together

**Classify triangles with sides (a) 8, 15, 17 and (b) 4, 6, 8.**

{{lines-3}}

:::


:::teacher-note

**Answer:** (a) 64 + 225 = 289 = 17²: right-angled. (b) 16 + 36 = 52 &lt; 64: obtuse.

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