---
title: "Triangles hold their shape"
subtitle: "Structures · Frames and trusses · Lesson 2"
---

# Triangles hold their shape

**Name:** {{field-24}} **Date:** {{field-15}} **Class:** {{field-15}}

> **Key question:** Why are bridges, cranes and towers full of triangles, and not squares?


:::teacher-note

**In one sentence:** Students watch a square frame on pins collapse under a sideways push, brace it with one diagonal, learn the counting rule (members + 3 = 2 × joints for a pin and a roller), and brace two- and three-storey towers with the fewest members.

**Students should be able to say:** I can explain why triangles keep their shape and squares don't. I can use the counting rule to say how many members a frame needs. I can brace a frame with the fewest members.

**Width:** the unmarked parts are the floor every student does (predict, run, investigate and make). Typical adds the modify practice; wider adds the real-world contexts. They add contexts, not difficulty. Students work in the online tutorial alongside this sheet.

:::


## Predict


:::keep-together

**Each member of the square can take 5000 N. The wind pushes 500 N sideways at D. The frame…**

☐ Slides off the roller

☐ Holds easily: 500 N is small

☐ Breaks one member

☐ Folds over: it changes shape without any member stretching

My prediction, and why:

{{lines-3}}

:::


:::teacher-note

**What happens:** It folds over. The members are strong enough, but a square on pins can lean without any member changing length, so nothing resists.

:::


## Run

Try it on the board in the tutorial. Was your prediction right? What was different?

{{lines-2}}

## Worked example: count the members


:::keep-together

### The rule

1. $\text{joints } j = 4,\; \text{members } m = 4$ — The square: 4 joints, 4 members.
2. $m + 3 = 2j$ — Each joint gives 2 ways to move (sideways and up); the pin and roller hold 3 of them. Each member holds one.
3. $4 + 3 = 7 \ne 8$ — One short: the square can move one way (it leans).
4. $5 + 3 = 8 = 2 \times 4 \;\checkmark$ — Add one diagonal: rigid, with none spare.

**A frame has 8 joints, on a pin and a roller. How many members does it need to be rigid with none spare?**

Answer: {{field-15}}

:::


:::teacher-note

**Answer:** 13

2 × 8 − 3 = 13.

:::


:::keep-together

### Find the mistake

**Zoe thinks she needs 15 members. Click the line where her working first goes wrong.**

```
 1  Zoe's frame has 6 joints, on a pin and a roller.
 2  The rule: members + 3 = 2 × joints.
 3  So members = 2 × 6 + 3 = 15.
 4  She needs 15 members to make it rigid.
```

Line: {{field-15}}

Why is it wrong?

{{lines-2}}

:::


:::teacher-note

**Answer:** line 3

Line 3: members + 3 = 2 × joints, so members = 2 × 6 − 3 = 9. She added 3 instead of taking it away.

:::


:::typical

## Vary: a taller tower


**Two storeys.** 

**Both diagonals.** 

Work in the tutorial. Plan first: what will you change, and how will you test it?

{{box-4}}

:::


## Rigid or not?


:::keep-together

### A crane arm

**A crane arm has 10 joints, on a pin and a roller. How many members does it need?**

Answer: {{field-15}}

:::


:::teacher-note

**Answer:** 17

2 × 10 − 3 = 17.

:::


:::keep-together

### Rigid?

**A frame has 7 joints and 10 members, on a pin and a roller. Is it rigid?**

☐ No: it needs 11

☐ Yes

☐ It has a spare member

:::


:::teacher-note

**Answer:** No: it needs 11

2 × 7 − 3 = 11, so with 10 it can change shape one way.

:::


:::keep-together

### A gate

**A wooden gate sags at the corner away from its hinges. What should you add?**

☐ A diagonal brace across the gate

☐ A third hinge on the same side

☐ Paint

☐ Thicker rails

:::


:::teacher-note

**Answer:** A diagonal brace across the gate

A diagonal turns the gate's rectangle into triangles, so it can't lean.

:::


## Make: brace a tower


**Three storeys.** 

**Evaluate.** 

Work in the tutorial. Plan first: what will you change, and how will you test it?

{{box-4}}

## Exit ticket

:::keep-together

**A frame has 9 joints on a pin and a roller. How many members does it need to be rigid with none spare?**

{{lines-3}}

:::


:::teacher-note

**Answer:** 2 × 9 − 3 = 15.

:::

