---
title: "Gear trains"
subtitle: "Mechanisms · Gears · Lesson 2"
---

# Gear trains

**Name:** {{field-24}} **Date:** {{field-15}} **Class:** {{field-15}}

> **Key question:** The bucket is now 1500 g: more than any pair in the box can lift. You can use as many gears as you like. How?


:::teacher-note

**In one sentence:** Students add a third gear between two others and find it changes only the direction (an idler), then put two gears on one axle to make a compound train, work out that stage ratios multiply, choose a train for a load no single pair can lift, and see why big ratios come in stages.

**Students should be able to say:** I can explain that an idler gear changes the direction of a turn but not the ratio. I can work out the overall ratio of a compound train by multiplying its stage ratios. I can choose a gear train that meets every criterion in a brief. I can explain why big ratios are built in stages.

**Width:** the unmarked parts are the floor every student does (predict, run, investigate and make). Typical adds the modify practice; wider adds the real-world contexts. They add contexts, not difficulty. Students work in the online tutorial alongside this sheet.

:::


## Predict


:::keep-together

**Put a 40-tooth gear between the 8 and the 24: 8 → 40 → 24. Compared with 8 → 24 on its own, the winch now…**

☐ Turns at the same speed with the same strength, but the other way round

☐ Turns faster, because the big gear spins it

☐ Turns 5 times slower and is 5 times stronger (40 ÷ 8)

☐ Turns 15 times slower and is 15 times stronger (5 × 3)

My prediction, and why:

{{lines-3}}

:::


:::teacher-note

**What happens:** Same speed, same strength, other direction. 40 ÷ 8 × 24 ÷ 40 = 24 ÷ 8: the idler's teeth cancel out, and each mesh reverses the turn.

:::


## Run

Try it on the board in the tutorial. Was your prediction right? What was different?

{{lines-2}}

## Worked example: two gears on one axle


:::keep-together

### Check 8 → 24 = 8 → 40, then 16 → 40 = 8 → 24

1. $\text{stage 1: } 24 \div 8 = 3$ — The motor's 8 drives a 24: a ratio of 3, as before.
2. $\text{stage 2: } 40 \div 8 = 5$ — An 8 on the 24's axle turns with it, and drives a 40: the next stage starts small again.
3. $3 \times 5 = 15$ — Stages multiply: the second stage slows down a gear that is already 3 times slower.
4. $120 \div 15 = 8 \text{ turns a minute}$ — Slower by the overall ratio.
5. $200 \times 15 = 3000 \text{ g}$ — Stronger by the same ratio.
6. $10 \div 8 = 1.25 \text{ min} = 75 \text{ s}$ — 1 m takes 10 winch turns.
7. $3000 \ge 1500 \;\checkmark \quad 75 \le 40 \;\times$ — Strong enough, but too slow. Too much ratio costs time.

Now 16 → 40 = 8 → 24. Stage 1 is $40 \div 16 = 2.5$. Start with the overall ratio.

**Now 16 → 40, then 8 → 24 on the same axle as the 40. What is the overall ratio?**

Answer: {{field-15}}

:::


:::teacher-note

**Answer:** 7.5

40 ÷ 16 = 2.5, 24 ÷ 8 = 3, and 2.5 × 3 = 7.5.

:::


:::keep-together

### Strength

**16 → 40 = 8 → 24: what is the heaviest bucket it can lift, in grams?**

Answer: {{field-15}}

:::


:::teacher-note

**Answer:** 1500

200 × 7.5 = 1500 g: just enough.

:::


:::keep-together

### Time and criteria

**16 → 40 = 8 → 24: how many seconds to lift the bucket 1 m?**

Answer: {{field-15}}

:::


:::teacher-note

**Answer:** 37.5

The winch turns 120 ÷ 7.5 = 16 times a minute. 10 turns ÷ 16 = 0.625 min = 37.5 s. It lifts 1500 g within 40 s: it passes.

:::


:::keep-together

### Find the mistake

**Kai thinks the train lifts the 1500 g bucket. Click the line where Kai's working first goes wrong.**

```
 1  Kai's train: 8 → 24, then an 8-tooth gear on the same axle as the 24 drives a 40.
 2  Stage 1: 24 ÷ 8 = 3
 3  Stage 2: 40 ÷ 8 = 5
 4  Overall ratio = 3 + 5 = 8
 5  Heaviest lift = 200 × 8 = 1600 g, so it lifts the 1500 g bucket.
```

Line: {{field-15}}

Why is it wrong?

{{lines-2}}

:::


:::teacher-note

**Answer:** line 4

Line 4: stage ratios multiply, they don't add. Each stage makes the next one 3 times (then 5 times) slower and stronger again: 3 × 5 = 15, so it lifts 3000 g (but takes 75 s).

:::


:::typical

## Vary: choose your train


**Meet the brief.** 

**Heavier still.** 

**Why stages?.** 

Work in the tutorial. Plan first: what will you change, and how will you test it?

{{box-4}}

:::


## Trains


:::keep-together

### Compound ratio

**10 → 30, then 10 → 20 on the same axle. What is the overall ratio?**

Answer: {{field-15}}

:::


:::teacher-note

**Answer:** 6

30 ÷ 10 = 3, 20 ÷ 10 = 2, and 3 × 2 = 6.

:::


:::keep-together

### Idler

**A simple train 8 → 16 → 24: the 16 is an idler. What is the ratio?**

Answer: {{field-15}}

:::


:::teacher-note

**Answer:** 3

Last ÷ first: 24 ÷ 8 = 3. The idler cancels out.

:::


:::keep-together

### Direction

**Three gears in a row, each meshing with the next. The motor gear turns clockwise. Which way does the last gear turn?**

☐ Anticlockwise

☐ Clockwise

☐ It depends on the sizes of the gears

:::


:::teacher-note

**Answer:** Clockwise

Two meshes: clockwise, then anticlockwise, then clockwise again.

:::


:::keep-together

### Speed

**Motor 120 turns a minute, train 8 → 40 = 8 → 24 (ratio 15). How many turns a minute does the winch make?**

Answer: {{field-15}}

:::


:::teacher-note

**Answer:** 8

120 ÷ 15 = 8.

:::


:::keep-together

### A clock

**A clock's hour hand turns 12 times slower than its minute hand. Its gears do this in two stages, 3 × 4. Which pairs could do it?**

☐ 8 → 96 in one pair, then an idler

☐ 8 → 24, then 8 → 40 on the same axle

☐ 12 → 24, then 12 → 36 on the same axle

☐ 8 → 24, then 10 → 40 on the same axle

:::


:::teacher-note

**Answer:** 8 → 24, then 10 → 40 on the same axle

24 ÷ 8 = 3 and 40 ÷ 10 = 4: 3 × 4 = 12.

:::


## Make: a brief only a train can meet


**A brief for a train.** 

**Evaluate.** Stretch: real meshes each lose about 5% of the turning force. Work out what your train can really lift, and whether it still meets your brief.

Work in the tutorial. Plan first: what will you change, and how will you test it?

{{box-4}}

## Exit ticket

:::keep-together

**A motor turning 240 times a minute drives 10 → 30, then 10 → 40 on the same axle. How fast does the output turn, and how many times stronger is it?**

{{lines-3}}

:::


:::teacher-note

**Answer:** Ratio 3 × 4 = 12, so 240 ÷ 12 = 20 turns a minute, 12 times stronger.

:::

